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(D) Let $E_{12}$ be the thermo-emf generated by the junction pair $(1, 2)$ and $E_{23}$ be the thermo-emf generated by the junction pair $(2, 3)$.Acco

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) Let $E_{12}$ be the thermo-emf generated by the junction pair $(1, 2)$ and $E_{23}$ be the thermo-emf generated by the junction pair $(2, 3)$.According to the law of intermediate temperatures in thermoelectric circuits,the total emf $E$ in the circuit is the algebraic sum of the emfs generated by individual junctions.When junction $1$ is at $50\,^{\circ}	ext{C}$ and junctions $2$ and $3$ are at $0\,^{\circ}	ext{C}$,the deflection is proportional to the emf $E_{12} = 14$ divisions.When junction $3$ is at $50\,^{\circ}	ext{C}$ and junctions $1$ and $2$ are at $0\,^{\circ}	ext{C}$,the deflection is proportional to the emf $E_{23} = 11$ divisions.When junction $2$ is at $50\,^{\circ}	ext{C}$ and junctions $1$ and $3$ are at $0\,^{\circ}	ext{C}$,the circuit effectively acts as two thermocouples in series,where the emf generated is the sum of the emfs of the two junctions,i.e.,$E = E_{12} + E_{23}$.Therefore,the total deflection is $14 + 11 = 25$ divisions.

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