Three rotten apples are accidentally mixed with fifteen good apples. Assuming the random variable $X$ to be the number of rotten apples in a draw of two apples,the variance of $X$ is

  • A
    $\frac{37}{153}$
  • B
    $\frac{57}{153}$
  • C
    $\frac{47}{153}$
  • D
    $\frac{40}{153}$

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$A$ person who tosses an unbiased coin gains two points for turning up a head and loses one point for a tail. If three coins are tossed and the total score $X$ is observed,then the range of $X$ is

$A$ random variable $X$ has the probability distribution as given below. Let $E = \{X \mid X \text{ is a prime number}\}$ and $F = \{X \mid X < 4\}$,then $P(E \cup F) = $
$\begin{array}{|c|c|c|c|c|c|c|c|c|} \hline X & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline P(X) & K & 2K & K^2 & 2K^2 & 5K^2 & K & K & 2K \\ \hline \end{array}$

If a variable takes values $0, 1, 2, ..., n$ with frequencies proportional to the binomial coefficients $^nC_0, ^nC_1, ..., ^nC_n$,find the mean of the distribution.

Difficult
View Solution

The cumulative distribution function of a discrete random variable $X$ is given by the following table:
$X = x$$-4$$-2$$0$$2$$4$$6$$8$$10$
$F(X = x)$$0.1$$0.3$$0.5$$0.65$$0.75$$0.85$$0.90$$1$

Then,calculate $\frac{P(X \leqslant 0)}{P(X > 0)}$.

$A$ random variable $X$ has the following probability distribution:
$X = x$$0$$1$$2$$3$$4$$5$$6$$7$
$P(X = x)$$0$$k$$2k$$2k$$3k$$k^2$$2k^2$$7k^2 + k$

Then $F(4) = $

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