Three resistors R_{1} = 5 Omega,R_{2} = 10 Om | vedclass

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(A) In a parallel circuit,the potential difference $(V)$ across each resistor is the same.According to Ohm's Law,$I = V / R$.Since $V$ is constant,the

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$R_{1}$

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(A) In a parallel circuit,the potential difference $(V)$ across each resistor is the same.According to Ohm's Law,$I = V / R$.Since $V$ is constant,the current $(I)$ is inversely proportional to the resistance $(R)$: $I \propto 1 / R$.Therefore,the resistor with the smallest resistance will have the highest current flowing through it.Given $R_{1} = 5 \Omega$,$R_{2} = 10 \Omega$,and $R_{3} = 30 \Omega$,the smallest resistance is $R_{1} = 5 \Omega$.Thus,the highest current flows through $R_{1}$.

Three resistors $R_{1} = 5 \Omega$,$R_{2} = 10 \Omega$,and $R_{3} = 30 \Omega$ are connected in parallel to a $12 \; V$ battery. Which resistor will have the highest current flowing through it?

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