State the formula correlating the electric current flowing in a conductor and the voltage applied across it. Also, show this relationship by drawing a graph. What would be the resistance of a conductor, if the current flowing through it is $0.35 \ A$ when the potential difference across it is $1.4 \ V$?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The relationship is defined by Ohm's Law, which states that: "Provided the physical conditions (like temperature) remain constant, the electric current flowing through a conductor is directly proportional to the potential difference applied across its two ends."
The formula is $V = I \times R$, where $V$ is potential difference, $I$ is current, and $R$ is resistance.
The graph of potential difference $(V)$ versus current $(I)$ is a straight line passing through the origin.
Given:
Potential difference $(V)$ = $1.4 \ V$
Current $(I)$ = $0.35 \ A$
Using Ohm's Law, the resistance $(R)$ is calculated as:
$R = \frac{V}{I}$
$R = \frac{1.4}{0.35}$
$R = 4 \ \Omega$
Thus, the resistance of the conductor is $4 \ \Omega$.

Explore More

Similar Questions

$A$ cylinder of a material is $10\, cm$ long and has a cross-section of $2\, cm^{2}$. If its resistance along the length is $20\, \Omega$,what will be its resistivity in number and units?

$A$ cell,a resistor,a key and an ammeter are arranged as shown in the circuit diagrams of the figure. The current recorded in the ammeter will be

Two conducting wires of the same material,equal length,and equal diameter are connected in series. How does the heat produced by the combination of resistance change?

On which factors does the resistivity of a conducting wire depend?

If a wire of resistance $R$ is melted and recast to half of its length,then the new resistance of the wire will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo