Three pipes A, B and C can fill a tank from e | vedclass

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(B) The rate of filling for pipes $A, B$ and $C$ is $\frac{1}{30}, \frac{1}{20}$ and $\frac{1}{10}$ of the tank per minute respectively.The total part

Vedclass · Accepted Answer

$\frac{6}{11}$

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(B) The rate of filling for pipes $A, B$ and $C$ is $\frac{1}{30}, \frac{1}{20}$ and $\frac{1}{10}$ of the tank per minute respectively.The total part of the tank filled in one minute by all three pipes is $\frac{1}{30} + \frac{1}{20} + \frac{1}{10} = \frac{2 + 3 + 6}{60} = \frac{11}{60}$.The ratio of the volumes of solutions $P, Q$ and $R$ discharged into the tank is equal to the ratio of the rates of the pipes: $\frac{1}{30} : \frac{1}{20} : \frac{1}{10} = 2 : 3 : 6$.Since the pipes are opened simultaneously and run for the same duration ($3$ minutes),the proportion of each solution in the mixture remains constant regardless of the total volume filled.Therefore,the proportion of solution $R$ in the liquid is $\frac{6}{2 + 3 + 6} = \frac{6}{11}$.

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