Three moles of oxygen are mixed with 2 , mole | vedclass

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(C) The number of moles of oxygen $(n_1 = 3)$ is diatomic,so its degrees of freedom $f_1 = 5$. The number of moles of helium $(n_2 = 2)$ is monatomic,

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$1.5$

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(C) The number of moles of oxygen $(n_1 = 3)$ is diatomic,so its degrees of freedom $f_1 = 5$. The number of moles of helium $(n_2 = 2)$ is monatomic,so its degrees of freedom $f_2 = 3$.The equivalent degrees of freedom for the mixture is given by $f_{mix} = \frac{n_1 f_1 + n_2 f_2}{n_1 + n_2}$.Substituting the values: $f_{mix} = \frac{3 	imes 5 + 2 	imes 3}{3 + 2} = \frac{15 + 6}{5} = \frac{21}{5} = 4.2$.The ratio of specific heats for the mixture is $\gamma_{mix} = 1 + \frac{2}{f_{mix}}$.$\gamma_{mix} = 1 + \frac{2}{4.2} = 1 + \frac{20}{42} = 1 + \frac{10}{21} = \frac{31}{21} \approx 1.476$.Rounding to the nearest provided option,the value is $1.5$.

Three moles of oxygen are mixed with $2 \, moles$ of helium. What will be the ratio of specific heats at constant pressure and constant volume for the mixture?

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