Three different objects of masses m_1, m_2 an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the law of conservation of energy,the potential energy at the top is converted into kinetic energy at the bottom.$mgh = \frac{1}{2}mv

Vedclass · Accepted Answer

$1 : 1 : 1$

Vedclass · Answer

(C) According to the law of conservation of energy,the potential energy at the top is converted into kinetic energy at the bottom.$mgh = \frac{1}{2}mv^2$Here,$m$ is the mass of the object,$g$ is the acceleration due to gravity,$h$ is the height,and $v$ is the final velocity.Canceling $m$ from both sides,we get $gh = \frac{1}{2}v^2$,which simplifies to $v = \sqrt{2gh}$.Since all three objects fall from the same height $h$ and are subject to the same acceleration due to gravity $g$,their final speeds will be independent of their masses.Therefore,the ratio of their speeds is $v_1 : v_2 : v_3 = \sqrt{2gh} : \sqrt{2gh} : \sqrt{2gh} = 1 : 1 : 1$.

Three different objects of masses $m_1, m_2$ and $m_3$ are allowed to fall from rest and from the same point $O$ along three different frictionless paths. The speeds of the three objects,on reaching the ground,will be in the ratio of

Similar Questions

When work is done on a body by an external force,its

$A$ force acts on a $2\,kg$ object so that its position is given as a function of time as $x = 3t^2 + 5$. What is the work done by this force in the first $5\,seconds$? ................ $J$

$A$ block of mass $1\,kg$ slides on a rough horizontal surface. If the speed of the block decreases from $10\,m/s$ to $8\,m/s$,the thermal energy developed in this process is .................. $J$.

$A$ body of mass $2 \, kg$ is released from point $A$. Its velocity at point $B$ is $4 \, m/s$,and it comes to rest at point $C$. The work done against friction is ............. $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module