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(D) When three coins are tossed together,the total number of possible outcomes is $2^3 = 8$.The sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, T

Vedclass · Accepted Answer

$\frac{7}{8}$

Vedclass · Answer

(D) When three coins are tossed together,the total number of possible outcomes is $2^3 = 8$.The sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Let $E$ be the event of getting at least one head.The complement event $E'$ is the event of getting no heads,which means getting all tails $(TTT)$.The number of outcomes for $E'$ is $1$.Therefore,$P(E') = \frac{1}{8}$.The probability of getting at least one head is $P(E) = 1 - P(E')$.$P(E) = 1 - \frac{1}{8} = \frac{7}{8}$.

Three coins are tossed together,then the probability of getting at least one head is

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