Three charges are placed at the vertices of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the charges at $A, B,$ and $C$ be $+Q, -Q,$ and $+Q$ respectively. The distance between any two vertices is $a$.The force on charge at $A$ due

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(C) Let the charges at $A, B,$ and $C$ be $+Q, -Q,$ and $+Q$ respectively. The distance between any two vertices is $a$.The force on charge at $A$ due to charge at $B$ is $F_B = \frac{1}{4\pi \varepsilon_0} \frac{Q^2}{a^2}$ (attractive,directed towards $B$).The force on charge at $A$ due to charge at $C$ is $F_C = \frac{1}{4\pi \varepsilon_0} \frac{Q^2}{a^2}$ (repulsive,directed away from $C$).Resolving these forces into components parallel and normal to $BC$:$1$. The components of $F_B$ and $F_C$ parallel to $BC$ are $F_B \cos 60^\circ$ and $F_C \cos 60^\circ$ respectively,both directed towards the left.$2$. The components of $F_B$ and $F_C$ normal to $BC$ are $F_B \sin 60^\circ$ (downwards) and $F_C \sin 60^\circ$ (upwards) respectively.Since $|F_B| = |F_C|$,the net force in the direction normal to $BC$ is $F_C \sin 60^\circ - F_B \sin 60^\circ = 0$.

Three charges are placed at the vertices of an equilateral triangle of side '$a$' as shown in the figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $BC$ is

Similar Questions

Two charges $Q$ are placed at opposite corners of a square. Two charges $q$ are placed at the other two corners. If the net electric force on $Q$ is zero,then $Q/q$ is equal to:

What is the net force on a $Cl^{-}$ ion placed at the centre of the $bcc$ structure of $CsCl$?

The distance between charges $5 \times 10^{-11} \, C$ and $-2.7 \times 10^{-11} \, C$ is $0.2 \, m$. The distance at which a third charge should be placed in order that it will not experience any force along the line joining the two charges is . . . . . . $m$.

Two identical charges repel each other with a force equal to $10 \text{ mg}$ wt when they are $0.6 \text{ m}$ apart in air $(g = 10 \text{ ms}^{-2})$. The value of each charge is:

Two point charges of $+2\,\mu C$ and $+6\,\mu C$ repel each other with a force of $12\,N$. If each is given an additional charge of $-4\,\mu C$,then the force will become:

Vedclass Test Series

Exam Paper Generator

Online Exam Module