A simple pendulum of period T has a metal bob | vedclass

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Question

(B) The period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to g

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Be less than $T$

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(B) The period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity.When a negatively charged bob oscillates above a positively charged plate,an electrostatic force of attraction acts on the bob in the downward direction.This electrostatic force adds to the gravitational force,effectively increasing the acceleration acting on the bob.Therefore,the effective acceleration $g_{eff} = g + \frac{F_e}{m}$ becomes greater than $g$.Since $T$ is inversely proportional to $\sqrt{g_{eff}}$,an increase in $g_{eff}$ results in a decrease in the time period $T$.Thus,the new period will be less than $T$.

$A$ simple pendulum of period $T$ has a metal bob which is negatively charged. If it is allowed to oscillate above a positively charged metal plate,its period will

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