Three capacitors of capacitance C (mu F) are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The effective capacitance of three capacitors connected in parallel is $C_p = C + C + C = 3C$.This combination is connected in series with a capac

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The effective capacitance of three capacitors connected in parallel is $C_p = C + C + C = 3C$.This combination is connected in series with a capacitor of capacitance $C$.The formula for the equivalent capacitance $C_{eq}$ of two capacitors in series is given by:$C_{eq} = \frac{C_p 	imes C}{C_p + C}$Substituting the given values:$3.75 = \frac{3C 	imes C}{3C + C}$$3.75 = \frac{3C^2}{4C}$$3.75 = \frac{3}{4}C$$C = \frac{3.75 	imes 4}{3}$$C = 1.25 	imes 4 = 5 \mu F$Therefore, the capacity of each capacitor is $5 \mu F$.

Three capacitors of capacitance $C$ ($\mu F$) are connected in parallel, and this combination is connected in series with another capacitor of capacitance $C$. If the effective capacitance is $3.75 \mu F$, then the capacity of each capacitor is: (in $\mu F$)

Similar Questions

What is a parallel connection of capacitors? Obtain the formula for the effective capacitance in the parallel combination of two different capacitors.

The total capacity of the system of capacitors shown in the adjoining figure between the points $A$ and $B$ is.....$\mu F$

Find the net capacitance between $A$ and $B$.

The equivalent capacitance between points $A$ and $B$ is

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\,V$ is applied to the outer plates of the two-capacitor system. The potential difference across the plates of the $4\,\mu F$ capacitor is ......... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module