The total capacity of the system of capacitor | vedclass

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(B) The circuit consists of capacitors arranged in a bridge-like structure. Let the nodes be $A$ and $B$. $1$. The two capacitors of $2 \, \mu F$ each

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$2$

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(B) The circuit consists of capacitors arranged in a bridge-like structure. Let the nodes be $A$ and $B$. $1$. The two capacitors of $2 \, \mu F$ each, connected in series on the right side, have an equivalent capacitance $C_1 = (2 	imes 2) / (2 + 2) = 1 \, \mu F$. $2$. This $C_1 = 1 \, \mu F$ is now in parallel with the middle $1 \, \mu F$ capacitor. Their equivalent is $C_2 = 1 + 1 = 2 \, \mu F$. $3$. Finally, this $C_2 = 2 \, \mu F$ is in series with the top $2 \, \mu F$ capacitor, resulting in $C_3 = (2 	imes 2) / (2 + 2) = 1 \, \mu F$. $4$. This $C_3 = 1 \, \mu F$ is in parallel with the leftmost $1 \, \mu F$ capacitor. $5$. The total equivalent capacitance is $C_{eq} = 1 + 1 = 2 \, \mu F$. Thus, the correct option is $B$.

The total capacity of the system of capacitors shown in the adjoining figure between the points $A$ and $B$ is.....$\mu F$

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