There are two points $P$ and $Q$ on a projectile with velocities $v_P$ and $v_Q$ respectively such that $v_P$ is perpendicular to $v_Q$ and $\alpha$ is the angle that $v_P$ makes with horizontal at point $P$. Find the correct option

  • A

    $\tan \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

  • B

    $\cos \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

  • C

    $\sec \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

  • D

    $\cot \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

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