(D) Let the number of fruits in the second basket be $x$.Therefore,the number of fruits in the first basket $= 2x$.The number of fruits in the third b

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(D) Let the number of fruits in the second basket be $x$.Therefore,the number of fruits in the first basket $= 2x$.The number of fruits in the third basket $= 2x \times \frac{3}{4} = \frac{3}{2}x$.The average of the fruits in all three baskets is given as $30$.So,$\frac{2x + x + \frac{3}{2}x}{3} = 30$.Multiplying by $3$,we get $2x + x + \frac{3}{2}x = 90$.$\frac{4x + 2x + 3x}{2} = 90$.$\frac{9x}{2} = 90$.$9x = 180$.$x = 20$.The number of fruits in the first basket $= 2x = 2 \times 20 = 40$.

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There are three baskets of fruits. The $1^{st}$ basket has twice the number of fruits in the $2^{nd}$ basket. The $3^{rd}$ basket has three-fourths of the fruits in the first. The average of the fruits in all the baskets is $30$. What is the number of fruits in the first basket?

A
$20$
B
$30$
C
$35$
D
$40$

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There are three baskets of fruits. The $1^{st}$ basket has twice the number of fruits in the $2^{nd}$ basket. The $3^{rd}$ basket has three-fourths of the fruits in the first. The average of the fruits in all the baskets is $30$. What is the number of fruits in the first basket?

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