The average weight of A, B and C is 84 , kg. | vedclass

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(B) The sum of the weights of $A, B$ and $C$ is $84 	imes 3 = 252 \, kg$.When $D$ joins,the sum of the weights of $A, B, C$ and $D$ is $80 	imes 4 =

Vedclass · Accepted Answer

$75$

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(B) The sum of the weights of $A, B$ and $C$ is $84 	imes 3 = 252 \, kg$.When $D$ joins,the sum of the weights of $A, B, C$ and $D$ is $80 	imes 4 = 320 \, kg$.Therefore,the weight of $D = 320 - 252 = 68 \, kg$.Given that $E$ is $3 \, kg$ heavier than $D$,the weight of $E = 68 + 3 = 71 \, kg$.When $E$ replaces $A$,the new group consists of $B, C, D$ and $E$. The sum of their weights is $79 	imes 4 = 316 \, kg$.Since $B + C + D + E = 316 \, kg$ and $E = 71 \, kg$,we have $B + C + D = 316 - 71 = 245 \, kg$.From the equation $A + B + C + D = 320 \, kg$,we can find $A$ by subtracting the sum of $B, C$ and $D$:$A = 320 - 245 = 75 \, kg$.

The average weight of $A, B$ and $C$ is $84 \, kg$. If $D$ joins,the average weight now is $80 \, kg$. If another person $E$,who is $3 \, kg$ heavier than $D$,replaces $A$,then the average weight of $B, C, D$ and $E$ becomes $79 \, kg$. What is the weight of $A$ in $kg$?

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