There are four concentric shells A, B, C and | vedclass

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Question

Let charge on $C$ be $q:$

$V_{C}=\frac{k q}{3 a}+\frac{k q^{\prime}}{3 a}-\frac{k q}{4 a}$

$V_{C}=0(	ext { earthed })$

$\frac{k q}{3 a}+\fra

Vedclass · Accepted Answer

$\frac{{Kq}}{{6a}}$

Vedclass · Answer

Let charge on $C$ be $q:$

$V_{C}=\frac{k q}{3 a}+\frac{k q^{\prime}}{3 a}-\frac{k q}{4 a}$

$V_{C}=0(	ext { earthed })$

$\frac{k q}{3 a}+\frac{k q^{\prime}}{3 a}-\frac{k q}{4 a}=0$

$q^{\prime}=\frac{-q}{4}$

$V_{A}=\frac{k q}{2 a}-\frac{k q / 4}{3 a}-\frac{k q}{4 a}=\frac{k q}{6 a}$

Therefore, $V_{A}-V_{C}=\frac{k q}{6 a}$

There are four concentric shells $A, B, C $ and $D $ of radii $ a, 2a, 3a$ and $4a$ respectively. Shells $B$ and $D$ are given charges $+q$ and $-q$ respectively. Shell $C$ is now earthed. The potential difference $V_A - V_C $ is :

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