Potential at a point $x$-distance from the centre inside the conducting sphere of radius $R$ and charged with charge $Q$ is
$\frac{Q}{R}$
$\frac{Q}{x}$
$\frac{Q}{{{x^2}}}$
$xQ$
The electric potential at the surface of an atomic nucleus $(Z = 50)$ of radius $9.0×{10^{ - 13}}\, cm$ is
Two identical metal balls of radius $r$ are at a distance $a (a >> r)$ from each other and are charged, one with potential $V_1$ and other with potential $V_2$. The charges $q_1$ and $q_2$ on these balls in $CGS$ esu are
A charge of $10 \,\mu C$ is placed at the origin of $x-y$ coordinate system. The potential difference between two points $(0, a)$ and $(a, 0)$ in volt will be
Two thin wire rings each having a radius $R$ are placed at a distance $d$ apart with their axes coinciding. The charges on the two rings are $ + q$ and $ - q$. The potential difference between the centres of the two rings is
Two unlike charges of magnitude $q$ are separated by a distance $2d$. The potential at a point midway between them is