There are 6 consecutive odd numbers in increa | vedclass

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Question

let the number be $(a-5),(a-3),(a-1),(a+1)(a+3)(a+5)$

Then the average of all six consecutive odd no.

$=\frac{(a-5)+(a-3)+(a-1)+(a+1)+(a+3)+(a+5

Vedclass · Accepted Answer

$8$

Vedclass · Answer

let the number be $(a-5),(a-3),(a-1),(a+1)(a+3)(a+5)$

Then the average of all six consecutive odd no.

$=\frac{(a-5)+(a-3)+(a-1)+(a+1)+(a+3)+(a+5)}{6}=a$

The value of "a' can be found by using the last statement $(a-5)^{2}+(a+5)^{2}=178 \Rightarrow a^{2}=64 a=8$

Average of all six number is $8.$

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