Average of a, b and c is 11; average of c, d | vedclass

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(A) Given that the average of $a, b, c$ is $11$,so the sum $a + b + c = 11 	imes 3 = 33$.Given that the average of $c, d, e$ is $17$,so the sum $c +

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$15 \frac{2}{3}$

Vedclass · Answer

(A) Given that the average of $a, b, c$ is $11$,so the sum $a + b + c = 11 	imes 3 = 33$.Given that the average of $c, d, e$ is $17$,so the sum $c + d + e = 17 	imes 3 = 51$.Given that the average of $e, f$ is $22$,so the sum $e + f = 22 	imes 2 = 44$.Given that the average of $e, c$ is $17$,so the sum $e + c = 17 	imes 2 = 34$.We need to find the sum $a + b + c + d + e + f$.From the sum $c + d + e = 51$ and $e + c = 34$,we can find $d = 51 - 34 = 17$.Now,the total sum is $(a + b + c) + (d) + (e + f) = 33 + 17 + 44 = 94$.The average of $a, b, c, d, e, f$ is $\frac{94}{6} = \frac{47}{3} = 15 \frac{2}{3}$.

Average of $a, b$ and $c$ is $11$; average of $c, d$ and $e$ is $17$; average of $e$ and $f$ is $22$ and average of $e$ and $c$ is $17$. Find out the average of $a, b, c, d, e$ and $f$?

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