The zeros of the quadratic polynomial p(x) = | vedclass

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(A) To find the zeros of the quadratic polynomial $p(x) = 3x^2 + 5x - 8$,we set $p(x) = 0$.$3x^2 + 5x - 8 = 0$We factorize the quadratic expression by

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$-\frac{8}{3}$ and $1$

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(A) To find the zeros of the quadratic polynomial $p(x) = 3x^2 + 5x - 8$,we set $p(x) = 0$.$3x^2 + 5x - 8 = 0$We factorize the quadratic expression by splitting the middle term. We need two numbers whose product is $3 	imes (-8) = -24$ and whose sum is $5$. These numbers are $8$ and $-3$.$3x^2 - 3x + 8x - 8 = 0$$3x(x - 1) + 8(x - 1) = 0$$(3x + 8)(x - 1) = 0$Setting each factor to zero:$3x + 8 = 0 \implies x = -\frac{8}{3}$$x - 1 = 0 \implies x = 1$Thus,the zeros are $-\frac{8}{3}$ and $1$.

The zeros of the quadratic polynomial $p(x) = 3x^2 + 5x - 8$ are $\ldots \ldots \ldots \ldots$

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