The graph of a linear polynomial p(x) = ax + | vedclass

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Question

(A) linear polynomial is defined as $p(x) = ax + b$,where $a 
eq 0$.To find the intersection with the $X$-axis,we set $p(x) = 0$.$ax + b = 0$$ax = -b

Vedclass · Accepted Answer

one point

Vedclass · Answer

(A) linear polynomial is defined as $p(x) = ax + b$,where $a 
eq 0$.To find the intersection with the $X$-axis,we set $p(x) = 0$.$ax + b = 0$$ax = -b$$x = -b/a$Since $a 
eq 0$,there is exactly one unique value of $x$ for which $p(x) = 0$.Therefore,the graph of a linear polynomial intersects the $X$-axis at exactly one point,which is $(-b/a, 0)$.

The graph of a linear polynomial $p(x) = ax + b$ intersects the $X$-axis at $\ldots \ldots \ldots \ldots$ (where $a \neq 0$).

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