The zeros of the cubic polynomial p(x) = ax^3 | vedclass

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(B) For a cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$ with zeros $\alpha, \beta,$ and $\gamma$:$1$. The sum of zeros is $\alpha + \beta + \gamma =

Vedclass · Accepted Answer

$-\frac{d}{a}$

Vedclass · Answer

(B) For a cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$ with zeros $\alpha, \beta,$ and $\gamma$:$1$. The sum of zeros is $\alpha + \beta + \gamma = -\frac{b}{a}$.$2$. The sum of the product of zeros taken two at a time is $\alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a}$.$3$. The product of the zeros is $\alpha\beta\gamma = -\frac{d}{a}$.Thus,the correct option is $B$.

The zeros of the cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$ where $a \neq 0$ and $a, b, c, d \in R$ are $\alpha, \beta,$ and $\gamma$. Then $\alpha \beta \gamma = \dots$

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