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(A) Young's modulus $Y$ is defined as the ratio of tensile stress to longitudinal strain:$Y = \frac{	ext{Tensile stress}}{	ext{Longitudinal strain}}

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Steel

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(A) Young's modulus $Y$ is defined as the ratio of tensile stress to longitudinal strain:$Y = \frac{	ext{Tensile stress}}{	ext{Longitudinal strain}}$Rearranging the formula,we get:$	ext{Tensile stress} = Y 	imes 	ext{Longitudinal strain}$For the same longitudinal strain,the tensile stress is directly proportional to the Young's modulus $(Y)$:$	ext{Stress} \propto Y$Since the Young's modulus of steel $(Y_{	ext{steel}})$ is much greater than that of rubber $(Y_{	ext{rubber}})$,it follows that:$	ext{Stress}_{	ext{steel}} > 	ext{Stress}_{	ext{rubber}}$Therefore,steel will have a greater tensile stress.

The Young's modulus for steel is much more than that for rubber. For the same longitudinal strain,which one will have greater tensile stress?

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