The work functions for tungsten and sodium ar | vedclass

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(C) The work function $W_0$ is related to the threshold wavelength $\lambda_0$ by the formula: $W_0 = \frac{hc}{\lambda_0}$.Since $h$ and $c$ are cons

Vedclass · Accepted Answer

$2791$

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(C) The work function $W_0$ is related to the threshold wavelength $\lambda_0$ by the formula: $W_0 = \frac{hc}{\lambda_0}$.Since $h$ and $c$ are constants, the work function is inversely proportional to the threshold wavelength: $W_0 \propto \frac{1}{\lambda_0}$.Therefore, we can write the ratio: $\frac{(W_0)_T}{(W_0)_{Na}} = \frac{(\lambda_0)_{Na}}{(\lambda_0)_T}$.Rearranging for the threshold wavelength of tungsten $(\lambda_0)_T$: $(\lambda_0)_T = \frac{(\lambda_0)_{Na} 	imes (W_0)_{Na}}{(W_0)_T}$.Substituting the given values: $(\lambda_0)_T = \frac{5460 	imes 2.3}{4.5}$.Calculating the result: $(\lambda_0)_T \approx 2791 	ext{ \AA}$.

The work functions for tungsten and sodium are $4.5 \text{ eV}$ and $2.3 \text{ eV}$ respectively. If the threshold wavelength $\lambda_0$ for sodium is $5460 \text{ \AA}$, the value of $\lambda_0$ for tungsten is ............ $\text{ \AA}$.

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