The work done in which of the following proce | vedclass

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(A) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta Q$ is the heat exchanged,$\Delta U$ is the change in i

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Adiabatic process

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(A) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta Q$ is the heat exchanged,$\Delta U$ is the change in internal energy,and $\Delta W$ is the work done by the system.In an adiabatic process,there is no exchange of heat with the surroundings,so $\Delta Q = 0$.Substituting this into the first law equation: $0 = \Delta U + \Delta W$.This simplifies to $\Delta W = -\Delta U$ or $\Delta U = -\Delta W$.If we consider the magnitude of work done on the system $(W_{on} = -\Delta W)$,then $W_{on} = \Delta U$.Thus,in an adiabatic process,the work done on the system is equal to the change in internal energy of the system.

The work done in which of the following processes is equal to the internal energy of the system?

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