The weight of a molecule of the compound C_{6 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molecular weight of $C_{60}H_{122}$ is calculated as: $(60 	imes 12) + (122 	imes 1) = 720 + 122 = 842 \ g/mol$. Using Avogadro's number $(N

Vedclass · Accepted Answer

$1.4 	imes 10^{-21} \ g$

Vedclass · Answer

(A) The molecular weight of $C_{60}H_{122}$ is calculated as: $(60 	imes 12) + (122 	imes 1) = 720 + 122 = 842 \ g/mol$. Using Avogadro's number $(N_A \approx 6.022 	imes 10^{23} \ mol^{-1})$,the mass of one molecule is given by: $	ext{Mass} = \frac{	ext{Molecular weight}}{N_A}$. $	ext{Mass} = \frac{842}{6.022 	imes 10^{23}} \approx 139.82 	imes 10^{-23} \ g = 1.398 	imes 10^{-21} \ g \approx 1.4 	imes 10^{-21} \ g$.

The weight of a molecule of the compound $C_{60}H_{122}$ is

Similar Questions

The number $\log_{2} 7$ is:

Among the following pairs of complexes,in which case is the $\Delta_0$ value higher for the first one than the second?

The amphoteric hydroxide is

If the ratio of diameters,lengths and Young's moduli of steel and brass wires shown in the figure are $p, q$ and $r$ respectively,then the corresponding ratio of increase in their lengths would be

The abundance of a species population within its habitat is called

Vedclass Test Series

Exam Paper Generator

Online Exam Module