The wavelengths of light absorbed by the comp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends o

Vedclass · Accepted Answer

$\lambda_1 > \lambda_3 > \lambda_2$

Vedclass · Answer

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends on the strength of the ligands.According to the spectrochemical series,the strength of the ligands is $en > H_2O$.Therefore,the crystal field splitting energy follows the order: $[Ni(en)_3]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(H_2O)_6]^{2+}$.Since $E = \frac{hc}{\lambda}$,the energy is inversely proportional to the wavelength.Thus,the order of wavelengths absorbed is: $[Ni(H_2O)_6]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(en)_3]^{2+}$.This corresponds to $\lambda_1 > \lambda_3 > \lambda_2$.

$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

The wavelengths of light absorbed by the complexes $[Ni(H_2O)_6]^{2+}$,$[Ni(en)_3]^{2+}$,and $[Ni(H_2O)_4en]^{2+}$ are $\lambda_1$,$\lambda_2$,and $\lambda_3$ respectively. The correct order of wavelengths is:

Similar Questions

The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

For which of the following complexes will the value of $\Delta_0$ be the lowest?

Complexes with $CN^-$ ligands are generally...

In the octahedral crystal field,the correct order of splitting for $I^{-}, H_2O, NH_3$ and $CN^{-}$ ligands is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module