(D) In $[CoF_{3}(H_{2}O)_{3}]$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^{6}$.Given $\Delta_{0} < P$,the c

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(D) In $[CoF_{3}(H_{2}O)_{3}]$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^{6}$.Given $\Delta_{0} The distribution of $6$ electrons in $d$-orbitals is $t_{2g}^{4} e_{g}^{2}$.$CFSE = [n(t_{2g}) \times (-0.4) + n(e_{g}) \times (0.6)] \Delta_{0}$$CFSE = [4 \times (-0.4) + 2 \times (0.6)] \Delta_{0}$$CFSE = [-1.6 + 1.2] \Delta_{0} = -0.4 \Delta_{0}$

Class 12 Chemistry Coordination Compounds Crystal Field theory

Difficult

The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

JEE MAIN 2020 All JEE MAIN

A
$-0.8 \Delta_{0}$
B
$-0.4 \Delta_{0} + P$
C
$-0.8 \Delta_{0} + 2P$
D
$-0.4 \Delta_{0}$

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Coordination Compounds

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The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

Similar Questions

Which complex shows the highest crystal field stabilisation energy?

The conditions and consequence that favour the $t_{2g}^3, e_g^1$ configuration in a metal complex are:

The homoleptic and octahedral complex of $Co^{2+}$ and $H_2O$ has $.......$ unpaired electron$(s)$ in the $t_{2g}$ set of orbitals.

Correct increasing order for the wavelength of absorption in the visible region for the complexes of $Co^{3+}$ is :

Explain crystal field splitting in octahedral complexes.

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