The wavelengths of Gamma rays,$X$-rays,and microwaves are respectively $\lambda_r, \lambda_x$,and $\lambda_m$. Then which of the following relations is correct?

One requires $11 \ eV$ of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in

If ${\lambda _v}$,${\lambda _x}$,and ${\lambda _m}$ represent the wavelengths of visible light,$X$-rays,and microwaves respectively,then:

The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula $E = hv$ (for energy of a quantum of radiation: photon) and obtain the photon energy in units of $eV$ for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?

Match List-$I$ with List-$II$:

List-$I$ (Electromagnetic waves)	List-$II$ (Wavelength)
$(a)$ $AM$ radio waves	$(i)$ $10^{-10} \, m$
$(b)$ Microwaves	$(ii)$ $10^{2} \, m$
$(c)$ Infrared radiations	$(iii)$ $10^{-2} \, m$
$(d)$ $X$-rays	$(iv)$ $10^{-4} \, m$

Choose the correct answer from the options given below:

$TV$ waves have a wavelength range of $1-10 \, m$. Their frequency range in $MHz$ is