The wavelength of the first line of Balmer series of hydrogen atom is $\lambda \,\mathop A\limits^o $. The wavelength of this line of a double ionised lithium atom $(Z = 3)$is
$\lambda /3$
$\lambda /9$
$\lambda /8$
$\lambda /27$
The first line in the Lyman series has wavelength $\lambda $. The wavlength of the first line in Balmer series is
In an atom for the electron to revolve around the nucleus, the necessary centripetal force is obtained from the following force exerted by the nucleus on the electron
If scattering particles are $56$ for ${90^o}$ angle then this will be at ${60^o}$ angle
Give a powerful way to determine an upper limit to the size of the electron.