The wavelength of the Lyman series is given b | vedclass

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(A) The Rydberg formula for the wavelength $\lambda$ of spectral lines in the hydrogen atom is given by $\frac{1}{\lambda} = R_H \left[ \frac{1}{n_1^2

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$\frac{4}{3 	imes 10967} 	ext{ cm}$

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(A) The Rydberg formula for the wavelength $\lambda$ of spectral lines in the hydrogen atom is given by $\frac{1}{\lambda} = R_H \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} ight]$,where $R_H$ is the Rydberg constant.For the Lyman series,the transition occurs to the ground state,so $n_1 = 1$. The longest wavelength (first line) corresponds to $n_2 = 2$.Substituting these values: $\frac{1}{\lambda} = R_H \left[ \frac{1}{1^2} - \frac{1}{2^2} ight] = R_H \left[ 1 - \frac{1}{4} ight] = R_H \left( \frac{3}{4} ight)$.Therefore,$\lambda = \frac{4}{3 R_H}$.Given $R_H \approx 10967 	ext{ cm}^{-1}$,we get $\lambda = \frac{4}{3 	imes 10967} 	ext{ cm}$.

The wavelength of the Lyman series is given by which of the following expressions?

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