The wavelength of light,while it is passing through water,is $540 \ nm$. The refractive index of water is $\frac{4}{3}$. The wavelength of the same light when it is passing through a transparent medium having a refractive index of $\frac{3}{2}$ is . . . . . . $nm$.

$A$ ray of light falls on a transparent glass slab with a refractive index (relative to air) of $1.62$. The angle of incidence for which the reflected and refracted rays are mutually perpendicular is

$A$ student sees the top edge and the bottom centre $C$ of a pool simultaneously from an angle $\theta$ above the horizontal as shown in the figure. The refractive index of water which fills up to the top edge of the pool is $\frac{4}{3}$. If $\frac{h}{x}=\frac{7}{4}$,then $\cos \theta$ is

The refractive index of water is $1.33$. The direction in which a man under water should look to see the setting sun is

$A$ beam of light is incident on a glass plate at an angle of $60^{\circ}$. The reflected ray is polarized. If the angle of incidence is $45^{\circ}$,then the angle of refraction is:

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Refractive index of glass is higher than that of air.
Reason $(R)$: Optical density of a medium is directly proportionate to its mass density which results in a proportionate refractive index.
In the light of the above statements,choose the most appropriate answer from the options given below.