The wavelength of a photon with energy 35 tex | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the

Vedclass · Accepted Answer

$35 	imes 10^{-12} 	ext{ m}$

Vedclass · Answer

(A) Given:Energy $E = 35 	ext{ keV} = 35 	imes 10^{3} 	imes 1.6 	imes 10^{-19} 	ext{ J} = 56 	imes 10^{-16} 	ext{ J}$.Using the formula for the wavelength of a photon:$E = \frac{hc}{\lambda} \implies \lambda = \frac{hc}{E}$Substituting the values:$\lambda = \frac{6.625 	imes 10^{-34} 	imes 3 	imes 10^{8}}{35 	imes 10^{3} 	imes 1.6 	imes 10^{-19}}$$\lambda = \frac{19.875 	imes 10^{-26}}{56 	imes 10^{-16}}$$\lambda \approx 0.3549 	imes 10^{-10} 	ext{ m} \approx 0.355 	imes 10^{-10} 	ext{ m} = 35.5 	imes 10^{-12} 	ext{ m}$.Rounding to the nearest provided option,the correct value is $35 	imes 10^{-12} 	ext{ m}$.

The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .
$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$

Similar Questions

$A$ photon has a wavelength of $3 \,nm$. Its momentum and energy, respectively, will be:
$[h = 6.63 \times 10^{-34} \,Js, c = 3 \times 10^8 \,m/s]$

Monochromatic light of frequency $6 \times 10^{14} \,Hz$ is produced by a laser. The power emitted is $2 \times 10^{-3} \,W$. How many photons per second on an average are emitted by the source? (Given $h = 6.63 \times 10^{-34} \,Js$)

Assertion: Mass of a moving photon varies inversely as the wavelength.
Reason: Energy of the particle $= \text{mass} \times (\text{speed of light})^2$

An electron and a photon have the same wavelength of $10^{-9} \, m$. If $E$ is the energy of the photon and $p$ is the momentum of the electron,then the magnitude of $E / p$ (in $SI$ unit) is

Which of the following relations is correct for a photon?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The wavelength of a photon with energy $35 \text{ keV}$ is . . . . . . .$(h = 6.625 \times 10^{-34} \text{ J s}, c = 3 \times 10^{8} \text{ m/s}, 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J})$