The voltage of an $AC$ source varies with time according to the equation $V = 100 \sin(100\pi t) \cos(100\pi t)$,where $t$ is in seconds and $V$ is in volts. Then:

  • A
    The peak voltage of the source is $100 \ V$.
  • B
    The peak voltage of the source is $50 \ V$.
  • C
    The peak voltage of the source is $100/\sqrt{2} \ V$.
  • D
    The frequency of the source is $50 \ Hz$.

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