The variation of molar conductivity with concentration of an electrolyte $X$ in aqueous solution is shown in the given figure.
The electrolyte $X$ is :

The equivalent conductance of $NaCl$,$HCl$,and $CH_{3}COONa$ at infinite dilution are $126.45$,$426.16$,and $91 \ \Omega^{-1} \ cm^{2} \ eq^{-1}$ respectively at $25^{\circ}C$. The equivalent conductance of acetic acid (at infinite dilution) would be:

Equivalent conductance of an electrolyte containing $NaF$ at infinite dilution is $90.1 \, \Omega^{-1} \, cm^2$. If $NaF$ is replaced by $KF$,what is the value of equivalent conductance? ........... $\Omega^{-1} \, cm^{2}$

The resistance of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $1500 \ \Omega$. If the conductivity of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $0.1466 \times 10^{-3} \ S \ cm^{-1}$,the cell constant of the conductivity cell in $cm^{-1}$ is:

The equivalent conductivities of $Al^{3+}$ and $SO_4^{2-}$ ions at infinite dilution are $189$ and $160 \ \Omega^{-1} cm^2 eq^{-1}$ respectively. What is the equivalent conductivity of $Al_2(SO_4)_3$ at infinite dilution?

For an $HCl$ solution at $25^o C$,the equivalent conductance at infinite dilution is $425 \ \Omega^{-1} \ cm^2 \ eq^{-1}$. The electrical conductivity of the $HCl$ solution is $3.825 \ \Omega^{-1} \ cm^{-1}$. If the degree of dissociation is $90\%$,what is the normality of the solution in $N$?