The resistance of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $1500 \ \Omega$. If the conductivity of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $0.1466 \times 10^{-3} \ S \ cm^{-1}$,the cell constant of the conductivity cell in $cm^{-1}$ is:

For a strong electrolyte,a plot of molar conductivity against (concentration)$^{1/2}$ is a straight line,with a negative slope. The correct unit for the slope is:

Resistance of a decimolar solution between two electrodes $0.02 \ m$ apart and $0.0004 \ m^2$ in area was found to be $50 \ \Omega.$ Specific conductance $(\kappa)$ is .......... $S \ m^{-1}$

Given below is the plot of the molar conductivity vs $\sqrt{concentration}$ for $KCl$ in aqueous solution. If,for the higher concentration of $KCl$ solution,the resistance of the conductivity cell is $100 \ \Omega$,then the resistance of the same cell with the dilute solution is '$x$' $\Omega$. The value of $x$ is $............$ ($Nearest$ $integer$)

The limiting molar conductivities $\wedge ^0$ for $NaCl$,$KBr$,and $KCl$ are $126$,$152$,and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\wedge ^0$ for $NaBr$ is ............ $S \ cm^2 \ mol^{-1}$.

What is the concentration of an electrolyte solution to have molar conductivity of $101 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and conductivity of $1.01 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$ at $298 \ K$ (in $M$)?