The van der Waals constants for HCl gas are a | vedclass

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(B) The formula for the critical temperature $(T_c)$ of a gas is given by: $T_c = \frac{8a}{27Rb}$ Given: $a = 3.6 \ atm \ L^2 \ mol^{-2}$ $b = 40 \ m

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$333.33$

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(B) The formula for the critical temperature $(T_c)$ of a gas is given by: $T_c = \frac{8a}{27Rb}$ Given: $a = 3.6 \ atm \ L^2 \ mol^{-2}$ $b = 40 \ mL \ mol^{-1} = 0.04 \ L \ mol^{-1}$ $R = 0.08 \ atm \ L \ K^{-1} \ mol^{-1}$ Substituting the values: $T_c = \frac{8 	imes 3.6}{27 	imes 0.08 	imes 0.04}$ $T_c = \frac{28.8}{27 	imes 0.0032}$ $T_c = \frac{28.8}{0.0864}$ $T_c = 333.33 \ K$

The van der Waals constants for $HCl$ gas are $a = 3.6 \ atm \ L^2 \ mol^{-2}$ and $b = 40 \ mL \ mol^{-1}$. The critical temperature of the gas is : ............. $K$ [ $R = 0.08 \ atm \ L \ K^{-1} \ mol^{-1}$ ]

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