The values of conductivity of some materials | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Materials with high conductivity (typically $> 10^2 \ S \ m^{-1}$) are classified as conductors.Given values in $S \ m^{-1}$ are: $2.1 	imes 10^3

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Materials with high conductivity (typically $> 10^2 \ S \ m^{-1}$) are classified as conductors.Given values in $S \ m^{-1}$ are: $2.1 	imes 10^3$,$1.0 	imes 10^{-16}$,$1.2 	imes 10$,$3.91$,$1.5 	imes 10^{-2}$,$1 	imes 10^{-1}$,$1.0 	imes 10^3$.$1$. $2.1 	imes 10^3$ (Conductor)$2$. $1.0 	imes 10^{-16}$ (Insulator)$3$. $1.2 	imes 10$ (Semiconductor)$4$. $3.91$ (Semiconductor)$5$. $1.5 	imes 10^{-2}$ (Semiconductor)$6$. $1 	imes 10^{-1}$ (Semiconductor)$7$. $1.0 	imes 10^3$ (Conductor)There are $2$ materials with high conductivity values ($2.1 	imes 10^3$ and $1.0 	imes 10^3$).Therefore,the number of conductors is $2$.

The values of conductivity of some materials at $298.15 \ K$ in $S \ m^{-1}$ are $2.1 \times 10^3$,$1.0 \times 10^{-16}$,$1.2 \times 10$,$3.91$,$1.5 \times 10^{-2}$,$1 \times 10^{-1}$,$1.0 \times 10^3$. The number of conductors among the materials is............

Similar Questions

What is the conductivity of $0.05 \ M$ $KCl$ solution if cell constant is $1.32 \ cm^{-1}$ and resistance is $528 \ \Omega$?

The specific conductance of a solution depends upon -

Two solutions of electrolytes $X$ and $Y$ are taken in two beakers and diluted by adding $500 \ mL$ of water. The molar conductivity $(\Lambda_m)$ of $X$ increases by $1.5$ times,while that of $Y$ increases by $20$ times. What could be the electrolytes $X$ and $Y$?

What is the resistance of $0.01 \ M \ KCl$ solution if its conductivity is $200 \ \Omega^{-1} \ cm^{-1}$ and cell constant is $1 \ cm^{-1}$?

For an electrolytic solution,specific conductance is $9.2 \times 10^{-2} \ \Omega^{-1} \ m^{-1}$,then calculate the value of molar conductance for a solution having a concentration of $0.02 \ M$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module