The values of $K_{sp}$ of two sparingly soluble salts $Ni(OH)_2$ and $AgCN$ are $2.0 \times 10^{-15}$ and $6 \times 10^{-17}$ respectively. Which salt is more soluble? Explain.
(N/A) For $AgCN$: $AgCN \rightleftharpoons Ag^{+} + CN^{-}$. Let solubility be $S_1$. $K_{sp} = S_1^2 = 6 \times 10^{-17}$. Thus,$S_1 = \sqrt{6 \times 10^{-17}} \approx 7.75 \times 10^{-9} \ M$.
For $Ni(OH)_2$: $Ni(OH)_2 \rightleftharpoons Ni^{2+} + 2OH^{-}$. Let solubility be $S_2$. $K_{sp} = (S_2)(2S_2)^2 = 4S_2^3 = 2.0 \times 10^{-15}$.
$S_2^3 = 0.5 \times 10^{-15} = 5 \times 10^{-16}$.
$S_2 = \sqrt[3]{5 \times 10^{-16}} \approx 7.94 \times 10^{-6} \ M$.
Comparing $S_1$ and $S_2$,$S_2 > S_1$,therefore $Ni(OH)_2$ is more soluble.
For $Ni(OH)_2$: $Ni(OH)_2 \rightleftharpoons Ni^{2+} + 2OH^{-}$. Let solubility be $S_2$. $K_{sp} = (S_2)(2S_2)^2 = 4S_2^3 = 2.0 \times 10^{-15}$.
$S_2^3 = 0.5 \times 10^{-15} = 5 \times 10^{-16}$.
$S_2 = \sqrt[3]{5 \times 10^{-16}} \approx 7.94 \times 10^{-6} \ M$.
Comparing $S_1$ and $S_2$,$S_2 > S_1$,therefore $Ni(OH)_2$ is more soluble.
Explore More
Similar Questions
Which of the following happens when $NH_{4}OH$ is added gradually to the solution containing $1 \ M \ A^{2+}$ and $1 \ M \ B^{3+}$ ions?
Given: $K_{sp}[A(OH)_{2}] = 9 \times 10^{-10}$ and $K_{sp}[B(OH)_{3}] = 27 \times 10^{-18}$ at $298 \ K$.
Given: $K_{sp}[A(OH)_{2}] = 9 \times 10^{-10}$ and $K_{sp}[B(OH)_{3}] = 27 \times 10^{-18}$ at $298 \ K$.
DifficultJEE MAIN 2025
View SolutionThe solubility product of silver bromide is $5.0 \times 10^{-13}$. The quantity of potassium bromide (molar mass taken as $120 \ g \ mol^{-1}$) to be added to $1 \ L$ of $0.05 \ M$ solution of silver nitrate to start the precipitation of $AgBr$ is
DifficultAIEEE 2010
View SolutionThe solubility product of $AgCl$ is $1.8 \times 10^{-10}$. Mixing equal volumes of which of the following solutions will result in the precipitation of $AgCl$?
Difficult
View SolutionThe solubility of $AgBr$ with solubility product $5.0 \times 10^{-13}$ at $298 \ K$ in $0.1 \ M$ $NaBr$ solution would be:
The correct representation for the solubility product of $SnS_2$ is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo