The value of $\int_{0}^{\sqrt{2}} [x^2] \, dx$,where $[.]$ denotes the greatest integer function.

  • A
    $2 - \sqrt{2}$
  • B
    $2 + \sqrt{2}$
  • C
    $\sqrt{2} - 1$
  • D
    $\sqrt{2} - 2$

Explore More

Similar Questions

The value of $\int_0^1 (1 + e^{-x^2}) \,dx$ is:

The integral $\int_0^1 \cot^{-1}(1 + x + x^2) dx$ is equal to:

The approximate value of $\int_{1}^{9} x^2 dx$ by using the trapezoidal rule with $4$ equal intervals is:

$\int_0^{\pi /4} \frac{dx}{\cos^4 x - \cos^2 x \sin^2 x + \sin^4 x} = $

Difficult
View Solution

The approximate value of $\int_1^3 \frac{dx}{2+3x}$ using Simpson's rule and dividing the interval $[1,3]$ into two equal parts is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo