The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ M$ $KCl$ solution is $520 \ \Omega$,the molar conductivity of $0.02 \ M$ solution (in $S \ cm^2 \ mol^{-1}$) is (Given: conductivity of $0.1 \ M$ $KCl$ solution $= 1.29 \ S \ m^{-1}$)

What is the effect of dilution on the equivalent conductivity of a strong electrolyte?

The specific conductivity of $N/10$ $KCl$ solution at $20\,^oC$ is $0.0212\,ohm^{-1}\,cm^{-1}$ and the resistance of the cell containing this solution at $20\,^oC$ is $55\,ohm$. The cell constant is ............. $cm^{-1}$.

At $298 \text{ K}$,the molar conductivity of $x\% \text{ (w/w)}$ $MX$ solution (aqueous) is $123.5 \text{ S cm}^2 \text{ mol}^{-1}$. The conductance of the same solution is $1.9 \times 10^{-3} \text{ S}$. The value of $x$ is . . . . . . $\times 10^{-2}$. (Given: cell constant = $1.3 \text{ cm}^{-1}$; molar mass of $MX$ is $75 \text{ g mol}^{-1}$,density of aqueous solution of $MX$ at $298 \text{ K}$ is $1.0 \text{ g mL}^{-1}$)

Calculate the molar conductivity of $NH_4OH$ at infinite dilution by using the following data:
$[\Lambda _m^o(NH_4Cl) = 129.8, \Lambda _m^o(KOH) = 248.0$ and $\Lambda _m^o(KCl) = 126 \ S \ cm^2 \ mol^{-1}]$

The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.