The two wires $A$ and $B$ of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire $A$ and wire $B$ is $20/11$. When the joined wire is kept under certain tension the elongations in the wires $A$ and $B$ are equal. If the length of wire $A$ is $2.2\text{ m}$,then the length of wire $B$ is . . . . . . m.
- A$1.1$
- B$2.22$
- C$1.21$
- D$4.44$
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