The two planets have radii r_1 and r_2 and th | vedclass

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Question

$g=\frac{G M}{r^{2}}=G \cdot \frac{4}{3} \frac{\pi r^{3} p}{r^{2}}=G \cdot \frac{4}{3} \pi r p$

$	herefore \quad \frac{g_{1}}{g_{2}}=\frac{r_{1} p

Vedclass · Accepted Answer

$r_1 p_1 : r_2 p_2$

Vedclass · Answer

$g=\frac{G M}{r^{2}}=G \cdot \frac{4}{3} \frac{\pi r^{3} p}{r^{2}}=G \cdot \frac{4}{3} \pi r p$

$	herefore \quad \frac{g_{1}}{g_{2}}=\frac{r_{1} p_{1}}{r_{2} p_{2}}$

The two planets have radii $r_1$ and $r_2$ and their densities $p_1$ and $p_2$ respectively. The ratio of acceleration due to gravity on them will be

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