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(B) Given the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{4}$.Let the amplitudes be $A_1$ and $A_2$. Since $I \propto A^2$,the ra

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$25:1$

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(B) Given the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{4}$.Let the amplitudes be $A_1$ and $A_2$. Since $I \propto A^2$,the ratio of amplitudes is $\frac{A_1}{A_2} = \sqrt{\frac{I_1}{I_2}} = \sqrt{\frac{9}{4}} = \frac{3}{2}$.The ratio of maximum to minimum intensity is given by the formula $\frac{I_{\max}}{I_{\min}} = \left( \frac{A_1 + A_2}{A_1 - A_2} \right)^2$.Substituting the values,we get $\frac{I_{\max}}{I_{\min}} = \left( \frac{3 + 2}{3 - 2} \right)^2 = \left( \frac{5}{1} \right)^2 = \frac{25}{1}$.Therefore,the ratio is $25:1$.

The two interfering waves have intensities in the ratio $9 : 4$. The ratio of intensities of maxima and minima in the interference pattern will be

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