The transfer characteristic curve of a transi | vedclass

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(A) Given: Input resistance $R_{	ext{in}} = 100\,\Omega$,Output resistance $R_{	ext{out}} = 100\,k\Omega = 10^5\,\Omega$.From the graph,the current

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$5 	imes 10^4, 2.5 	imes 10^6$

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(A) Given: Input resistance $R_{	ext{in}} = 100\,\Omega$,Output resistance $R_{	ext{out}} = 100\,k\Omega = 10^5\,\Omega$.From the graph,the current gain $\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{(20 - 5) 	imes 10^{-3} 	ext{ A}}{(400 - 100) 	imes 10^{-6} 	ext{ A}} = \frac{15 	imes 10^{-3}}{300 	imes 10^{-6}} = \frac{15000}{300} = 50$.Voltage gain $A_V = \beta 	imes \frac{R_{	ext{out}}}{R_{	ext{in}}} = 50 	imes \frac{10^5}{100} = 50 	imes 10^3 = 5 	imes 10^4$.Power gain $A_P = \beta 	imes A_V = 50 	imes (5 	imes 10^4) = 250 	imes 10^4 = 2.5 	imes 10^6$.

The transfer characteristic curve of a transistor,having input and output resistance $100\,\Omega$ and $100\,k\Omega$ respectively,is shown in the figure. The voltage and power gain are respectively:

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