The total number of lone pairs of electrons i | vedclass

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(D) To determine the total number of lone pairs in $N_2O_3$,we look at its Lewis structure.In the structure of $N_2O_3$ $(O=N-O-N=O)$,the distribution

Vedclass · Accepted Answer

$8$

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(D) To determine the total number of lone pairs in $N_2O_3$,we look at its Lewis structure.In the structure of $N_2O_3$ $(O=N-O-N=O)$,the distribution of lone pairs is as follows:$1$. Each terminal oxygen atom $(=O)$ has $2$ lone pairs.$2$. The central oxygen atom $(-O-)$ has $2$ lone pairs.$3$. Each nitrogen atom has $1$ lone pair.Total lone pairs = $(2 	imes 2) + 2 + (2 	imes 1) = 4 + 2 + 2 = 8$.Thus,the total number of lone pairs is $8$.

The total number of lone pairs of electrons in $N_2O_3$ is

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