(C) For $H_2O_2$ $(H-O-O-H)$,the bond order $(B.O.)$ is $1$.For $O_2$ $(O=O)$,the bond order $(B.O.)$ is $2$.For $O_3$ (Resonance hybrid),the bond ord

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(C) For $H_2O_2$ $(H-O-O-H)$,the bond order $(B.O.)$ is $1$.For $O_2$ $(O=O)$,the bond order $(B.O.)$ is $2$.For $O_3$ (Resonance hybrid),the bond order $(B.O.)$ is $1.5$.Bond length is inversely proportional to bond order $(B.O.)$.Order of $B.O.$: $O_2 (2) > O_3 (1.5) > H_2O_2 (1)$.Therefore,the order of bond length is: $II < III < I$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Mix Examples-Chemical Bonding

Medium

The correct order for $O-O$ bond length in the given substances is:
$I.$ $H_2O_2$
$II.$ $O_2$
$III.$ $O_3$

A
$I < II < III$
B
$II < I < III$
C
$II < III < I$
D
$III < I < II$

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Mix Examples-Chemical Bonding

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The correct order for $O-O$ bond length in the given substances is:$I.$ $H_2O_2$$II.$ $O_2$$III.$ $O_3$

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Which one of the following statements is correct?

If compound $MX_4$ is non-polar and has no lone pair at the central atom,then the bond angle $\angle XMX$ in the compound may be:

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The correct order for $O-O$ bond length in the given substances is:
$I.$ $H_2O_2$
$II.$ $O_2$
$III.$ $O_3$