The total momentum of the molecules of 1 ,gm | vedclass

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(D) The total momentum of the gas molecules is the vector sum of the individual momenta of all molecules.$\vec{P}_{total} = \sum m_i \vec{v}_i = N \cd

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(D) The total momentum of the gas molecules is the vector sum of the individual momenta of all molecules.$\vec{P}_{total} = \sum m_i \vec{v}_i = N \cdot m \cdot \vec{v}_{avg}$In a container at rest,the gas molecules move in random directions.The average velocity $\vec{v}_{avg}$ of the gas molecules at any temperature is always zero because for every molecule moving with velocity $\vec{v}$,there is a statistically equal probability of another molecule moving with velocity $-\vec{v}$.Therefore,the total momentum $\vec{P}_{total} = M \vec{v}_{avg} = 0$.

The total momentum of the molecules of $1 \,gm$ $mol$ of a gas in a container at rest at $300 \,K$ is

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