The time period of oscillation of a bar magnet suspended horizontally along the magnetic meridian is $T_0$. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be
$\frac{{{T_0}}}{2}$
$\frac{{{T_0}}}{{\sqrt 2 }}$
$\sqrt 2 {T_0}$
$2{T_0}$
A vibration magnetometer is placed at the south pole; then its the time period will be
Tangent galvanometer is used to measure
If the number of turns and radius of cross section of the coil of a tangent galvanometer are doubled, then the reduction factor $K$ will become
Vibration magnetometer works on the principle of
Using a bar magnet $ P,$ a vibration magnetometer has time period $2$ $seconds$. When a bar $Q$ (identical to $P$ in mass and size) is placed on top of $P$, the time period is unchanged. Which of the following statements is true