The temperature of a blackbody radiation encl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy density $u$ of blackbody radiation at temperature $T$ is given by $u = aT^4$,where $a$ is the radiation constant. The total energy $E$

Vedclass · Accepted Answer

Information not sufficient

Vedclass · Answer

(D) The energy density $u$ of blackbody radiation at temperature $T$ is given by $u = aT^4$,where $a$ is the radiation constant. The total energy $E$ in a container of volume $V$ is $E = uV = aVT^4$. The heat required to increase the temperature from $T_1$ to $T_2$ is $\Delta E = aV(T_2^4 - T_1^4)$. Since the volume $V$ of the container is not provided in the problem statement,it is impossible to calculate the exact numerical value of the heat required. Therefore,the information provided is insufficient.

The temperature of a blackbody radiation enclosed in a container of volume $V$ is increased from $100^{\circ} C$ to $1000^{\circ} C$. The heat required in the process is

Similar Questions

$A$ sphere,a cube,and a thin circular plate,all made of the same material and having the same mass,are initially heated to a temperature of $1000^{\circ}C$. Which one of these will cool first?

If Earth did not have an atmosphere,the temperature would be . . . . . . .

Which of the following laws states that "good absorbers of heat are good emitters"?

Define thermal radiation and radiant energy and explain Prevost's theory of heat exchange.

For an opaque body,the coefficient of transmission is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module